The output in the Independent Samples Test table includes two rows: Equal variances assumed and Equal variances not assumed. This implies that if we reject the null hypothesis of Levene's Test, it suggests that the variances of the two groups are not equal i.e., that the homogeneity of variances assumption is violated. H 1: σ 1 2 - σ 2 2 ≠ 0 ("the population variances of group 1 and 2 are not equal") H 0: σ 1 2 - σ 2 2 = 0 ("the population variances of group 1 and 2 are equal") SPSS conveniently includes a test for the homogeneity of variance, called Levene's Test, whenever you run an independent samples t test. Recall that the Independent Samples t Test requires the assumption of homogeneity of variance - i.e., both groups have the same variance. The generalization of "Student's" problem when several different population variances are involved. Extremely unbalanced designs increase the possibility that violating any of the requirements/assumptions will threaten the validity of the Independent Samples t Test.ġ Welch, B.
#Spss 12 doesn't work plus#
There are also a number of functions that perform different types of concatenation: CATS, CATT, CATX and CATQ plus other operations on character values.Your data must meet the following requirements: I'm not sure if I remember the function SUBST from SPSS, but it does not exist in SAS.
#Spss 12 doesn't work code#
HINT: Before even attempting a macro make sure you have the code running as intended, the data step I indicated you could replace the two values of &nr in the body with 3 and should run. Run /* very good idea to explicitly indicate the end of a data step, especially when using macros*/ If A_rank = I then do /* the do indicates a block of statements to execute when the condition is true, you were missing this in your and only the first bit was attempting to execute*/ I think you can get this with array processing and if you can live slightly different variable names such as event_type_1 instead of event_1_type it gets pretty easy.Īrray type Event_type_1 - Event_type_&nr Īrray date Event_date_1 - Event_date_&nr The code you are using would replace the outputset NR times. A description of how it "doesn't seem to work" is a good idea.Īre generating an error and it maybe something about an undefined array reference.